A body weighing 9 kg is fixed on a spring with a stiffness of k = 100N / m. Find the natural frequency.

Frequency (V) is inversely proportional to period (T):
V = 1 / T
The period can be found using the formula:
T = 2Pi * √m / k
T = 2 * 3.14 * √9 / 100 = 6.28 * √0.09 = 6.28 * 0.03 = 1.884 s
V = 1 / 1.884 = 0.531 Hz
Answer: V = 0.531 Hz



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