A body weighing m1 = 0.4 kg is acted upon by two forces: F1 = 3N and F2 = 4N. Determine the acceleration of the body

A body weighing m1 = 0.4 kg is acted upon by two forces: F1 = 3N and F2 = 4N. Determine the acceleration of the body if the forces are directed at an angle of 0 degrees.

The resulting F of these forces is:
F = 4 + 3 = 7H, since F1 and F2 are directed at an angle of 0.
According to Newton’s second law, F = ma, whence a = 7 / 0.4 = 17.5 m / s ^ 2.
Answer: 17.5m / s ^ 2.



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