A body with a mass of 100 g was moving with constant acceleration for 5 s, while its speed

A body with a mass of 100 g was moving with constant acceleration for 5 s, while its speed increased from 5 cm / s to 25 cm / s. Determine the work of the force acting on the body.

Given:

m = 100 grams = 0.1 kilograms – body weight;

v0 = 5 cm / s (centimeters per second) = 0.05 m / s (meters per second) – the initial speed of the body;

v1 = 25 cm / s = 0.25 m / s – the final velocity of the body;

t = 5 seconds – the period of time during which the speed of the body changed from v0 to v1.

It is required to determine A (Joule) – the work of the force acting on the body.

Let’s find the acceleration with which the body moved:

a = dv / t = (v1 – v0) / t = (0.25 – 0.05) / 5 = 0.2 / 5 = 0.04 m / s2.

During time t, the body has passed a path equal to:

S = v0 * t + a * t ^ 2/2 = 0.05 * 5 + 0.04 * 5 ^ 2/2 = 0.25 + 0.02 * 25 = 0.25 + 0.5 = 0, 75 meters.

The force under which the body moved is equal to:

F = m * a = 0.1 * 0.04 = 0.004 Newton.

Then the work will be equal to:

A = F * S = 0.004 * 0.75 = 0.003 Joule.

Answer: the work of force will be equal to 0.003 Joule.