A body with a mass of 2 kg falls from a height of 20 m. What is its potential energy after 1 s of fall?

Initial data: m (mass) = 2 kg, h (height) = 20 m, t (fall time) = 1 s.

Constant values: a = g (acceleration of gravity) = 10 m / s ^ 2.

1) Calculate the distance that the body will travel in 1 second of fall (we consider the fall free):

S = h1 = g * t ^ 2/2 = 10 * 1 ^ 2/2 = 5 m.

2) Let’s calculate the height at which the body is located:

h2 = h – h1 = 20 – 5 = 15 m.

3) Potential energy:

Ep = m * g * h2 = 2 * 10 * 15 = 300 J.

Answer: The potential energy of the body after 1 s fall is 300 J.