A body with a mass of 2 kg, moving evenly in 4 s, changed its speed from 1 m / s to 2 m / s.

A body with a mass of 2 kg, moving evenly in 4 s, changed its speed from 1 m / s to 2 m / s. Determine what force acted on the body in the direction of its movement.

To find out the force acting in the direction of motion of the represented body, consider the formula: Fx = mt * a = mt * (V – V0) / t, where mt is the body weight (mt = 2 kg); V is the achieved speed (V = 2 m / s); V0 – speed before acceleration (V0 = 1 m / s); t is the growth time of the speed (t = 4 s).

Let’s calculate: Fx = mt * (V – V0) / t = 2 * (2 – 1) / 4 = 0.5 N.

Answer: In the direction of motion of the represented body, a force of 0.5 N acted.