A body with a mass of 4 kg is acted upon by a constant force F = 6 N directed towards the initial velocity.

A body with a mass of 4 kg is acted upon by a constant force F = 6 N directed towards the initial velocity. The origin of the path length coincides with the initial position of the body. Initial speed V0 = 5 m / s. What is the law of body motion?

m = 4 kg.

F = 6 N.

V0 = 5 m / s.

S (t) -?

According to Newton’s 2 law, if the body is acted upon by a force F constant in direction and modulus, then the body will move with constant acceleration a, the value of which is determined by the formula: a = F / m.

a = 6 N / 4 kg = 1.5 m / s ^ 2.

For uniformly accelerated movement, the dependence of the distance traveled on time has the form: S (t) = V0 * t + a * t ^ 2/2, where V0 is the initial speed of movement, a is the acceleration of movement.

The law of motion of the body will have the form: S (t) = 5 * t + 1.5 * t ^ 2/2 = 5 * t + 0.75 * t ^ 2.

The speed of the body will change according to the law: V (t) = V0 + a * t.

V (t) = 5 + 1.5 * t.

Answer: S (t) = 5 * t + 0.75 * t ^ 2.