A body with a mass of m = 0.4 kg falls from a state of rest from a height of h = 1 m, with an acceleration

A body with a mass of m = 0.4 kg falls from a state of rest from a height of h = 1 m, with an acceleration of a = 8 m / s ^ 2. Determine △ p- Change in momentum of the body

To calculate the change in the momentum of a falling body, we use the formula: ΔР = Р2 – Р1 = m * Vк – 0 = m * √ (2a * h).

Values of variables: m – body weight (m = 0.4 kg); a – acceleration when falling (a = 8 m / s2); h – initial height (h = 1 m).

Calculation: ΔР = m * √ (2a * h) = 0.4 * √ (2 * 8 * 1) = 1.6 N * s.

Answer: The momentum of the falling body changed (increased) by 1.6 N * s.



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