A body with a mass of m = 5 kg is lifted with an acceleration of a = 2 m / s2. Determine the work

A body with a mass of m = 5 kg is lifted with an acceleration of a = 2 m / s2. Determine the work of force during the first five seconds.

Data: m (mass of the lifted body) = 5 kg; a (body acceleration) = 2 m / s2; t (considered duration of ascent) = 5 s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Resultant force: m * a = F – m * g, whence F = m * (a + g) = 5 * (2 + 10) = 60 N.

2) Distance traveled: h = S = Vn * t + a * t ^ 2/2 = 0 + 2 * 55/2 = 25 m.

3) Work performed: A = F * h = 60 * 25 = 1500 J.

Answer: The work of the force applied to the lifted body is 1500 J.