A body with a volume of 4 dm ^ 3 has a mass of 4 kg. Will the body drown in gasoline?

We translate all the values ​​from given to the SI system:
V = 4dm³ = 0.004m³.
When the body is in water, we write the expression according to Newton’s second law, taking into account that the body is motionless:
-m * g + Fa = 0
m * g = Fa
A buoyant force equal to the weight of the displaced fluid acts on a body immersed in a liquid, and is called the Archimedes force:
Fа = ρ * g * V, where ρ is the density of the liquid, g is the acceleration of gravity of a body raised above the Earth g = 9.8 m / s², V is the volume of the body.
The condition for the body to sink is m * g> Fa
Let’s define them:
According to the reference book, the density of gasoline is 710 kg / m³.
Fa = ρ * g * V = 710 * 9.8 * 0.004 = 27.8 N
m * g = 4 * 9.8 = 39.2 H
It turns out that the force of Archimedes is less, which means the body will drown.
Answer: the body will drown.

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