A body with an initial speed of 10 m / s moves with an acceleration a = -2 m / s2. determine the path covered by the body in 8s.

To find the path traversed by the body in question in 8 seconds of slow motion, we apply the formula: S = Vn * t + a * t ^ 2/2.

Variables: Vн – initial speed (Vн = 10 m / s); t – elapsed time (t = 8 s); a – acceleration (a = -2 m / s2); , we take into account that the body should stop after 5 s: t = (0 – Vn) / a = -10 / (-2) = 5 s.

Calculation: S = Vn * t + a * t ^ 2/2 = 10 * 5 + (-2) * 5 ^ 2/2 = 25 m.

Answer: In 8 seconds, the body in question will travel 25 meters and stop.