A body with mass = 1.32 kg moves on a horizontal surface with acceleration = 12.6 m / s2 under the action

A body with mass = 1.32 kg moves on a horizontal surface with acceleration = 12.6 m / s2 under the action of a horizontal external force. Find the modulus of the external force if a friction force = 2.54 N. acts between the surface and the body.

To find the modulus of the acting external force, we will project all forces on the ОХ axis: m * a = F – Ftr, from where we express: F = m * a + Ftr.

Values of variables: m – body weight (m = 1.32 kg); a – acquired acceleration (a = 12.6 m / s2); Ftr is the effective friction force (Ftr = 2.54 N).

Calculation: F = m * a + Ftr = 1.32 * 12.6 + 2.54 = 19.172 N.

Answer: The modulus of the acting external force is 19.172 N.