A body with mass m = 50 kg moves along a horizontal surface under the action of a horizontally directed force F = 100H.

A body with mass m = 50 kg moves along a horizontal surface under the action of a horizontally directed force F = 100H. What is the acceleration of a body if it is known that the coefficient of friction between the body and the surface is h = 0, 2?

Let us find the resultant of all forces acting on a given body according to Newton’s second law: ma = Fthrust – Friction, where the horizontally directed thrust force is given in the condition Fthrust = 100 N. And the friction force is found through the reaction force of the support N = mg; F friction = µ • N = µ • mg. The friction coefficient is µ = 0.2, g = 9.8 N / kg, and the body weight by the condition m = 50 kg. In order to determine what the acceleration is equal to, we express it from Newton’s law: a = (Fthrust – µ • mg): m. Substitute the known values: a = (100 N – 0.2 • 50 kg • 9.8 N / kg): 50 kg = 0.04.
Answer: 0, 04.