A boiler with a resistance of 120 ohms was placed in a vessel with 500 grams of water and a 220-volt network was turned on

| August 10, 2021 | education

A boiler with a resistance of 120 ohms was placed in a vessel with 500 grams of water and a 220-volt network was turned on. How many degrees the water will heat up in 10 minutes.

It is known from the condition that a boiler with a resistance R = 120 Ohm was placed in a vessel with water m = 500 grams = 0.5 and a network with a voltage of U = 220 Volts was switched on. How many degrees the water will heat up in t = 10 minutes = 10 * 60 = 600 s.

c = 4200 J / (kg * C °).

Let’s apply the following formulas for the solution:

UIt = cmT;

U ^ 2t = cmTR;

We express T from the formula:

T = U ^ 2t / cmR;

We just have to substitute the values into the resulting formula and make calculations:

T = (220 ^ 2 * 600) / (4200 * 0.5 * 120) = 115 ° the water heats up by 115 ° and begins to evaporate.



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