A bollon with a volume of 0.5 • 10-3 m 3 contains 2 kg of oxygen O2 at a temperature of 15 degrees

A bollon with a volume of 0.5 • 10-3 m 3 contains 2 kg of oxygen O2 at a temperature of 15 degrees. Determine the gas pressure in the cylinder.

Given:
V = 0.5 * 10 ^ -3 m ^ 3
m (O2) = 2 kg = 2000 g
t = 15 C = 288 K
M (O2) = 16 * 2 = 32 g / mol – molar mass of oxygen
R -?
p * V = m * R * T / M, where R = 8.31 J / mol * K is the universal gas constant
pressure is equal to:
p = m * R * T / V * M
p = 2000 * 8.31 * 288 / 0.5 * 10 ^ -3 * 32 = 299 * 10 ^ 5 Pa
Answer: p = 299 * 10 ^ 5 Pa