A bomb was dropped from a plane flying horizontally at an altitude of 4 km at a speed of 720 km / h.

A bomb was dropped from a plane flying horizontally at an altitude of 4 km at a speed of 720 km / h. At what distance from the target was it dropped if it hit the target?

These tasks: h (the height at which the aircraft, bomb is located) = 4 km = 4000 m; Vg (horizontal speed of the aircraft, bomb) = 720 km / h = 200 m / s.

Constants: g (acceleration due to gravity) = 9.81 m / s2.

1) The duration of the fall of the bomb: S = h = a * t^2 / 2 = g * t^2 / 2, whence we express: t = √ (2h / g) = √ (2 * 4000 / 9.81) = 28.557 s.

2) Distance from the drop point to the target: Sg = Vg * t = 200 * 28.557 = 5711 m.

Answer: The distance from the bomb drop point to the target is 5711 m.