A bomb weighing 250 kg freely falls from a height of 800 m. What is its potential and kinetic
| March 3, 2021 | education
A bomb weighing 250 kg freely falls from a height of 800 m. What is its potential and kinetic energy at an altitude of 100 m from the Earth’s surface?
m = 250 kg.
g = 10 m / s2.
h = 800 m.
h1 = 100 m.
Ek1 -?
En1 -?
The potential energy of a body En with a mass m raised to a height h above the earth’s surface is determined by the formula: En = m * g * h, where g is the acceleration of gravity.
En = m * g * h.
Ep = 250 kg * 10 m / s2 * 800 m = 2,000,000 J.
En1 = m * g * h1.
Ep1 = 250 kg * 10 m / s2 * 100 m = 250,000 J.
If we neglect the air resistance, then the law of conservation of total mechanical energy is valid for the bomb: En = Ek1 + En1.
Ek1 = En – En1.
Ek1 = 2,000,000 J – 250,000 J = 1,750,000 J.
Answer: En1 = 250,000 J, Ek1 = 1,750,000 J.
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