A box weighing 100 kg is pulled along the floor with an acceleration of 0.2 m / s ^ 2 applying a force of 200 N.

A box weighing 100 kg is pulled along the floor with an acceleration of 0.2 m / s ^ 2 applying a force of 200 N. What is the coefficient of friction? Find path and speed in 5 seconds

Given:

m = 100 kg;

a = 0.2 m / s ^ 2;

F = 200 H;

t = 5 s;

To find:

u -?

S -?

v -?

Solution:

First, we find the coefficient of friction, expressing it from the formula F = u * m * g;

u = F / m * g = 200/100 * 10 = 0.2;

In order to find the path, it is enough to simply substitute the values into the formula:

S = a * t ^ 2/2 = 0.2 * 5 ^ 2/2 = 2.5 m;

You can also find speed, we have all the values;

v = a * t = 0.2 * 5 = 1 m / s;

Answer: the coefficient of friction is 0.2, the path is 2.5 meters, the speed is 1 m / s.