A box with parts weighs 500 N. How much force is required to move this box evenly
| April 21, 2021 | education
A box with parts weighs 500 N. How much force is required to move this box evenly on a horizontal floor if the friction force is 0.05 of the weight of the box?
P = 500 N.
Ftr = 0.05 * R.
F -?
According to 1 Newton’s law: a body can be in a state of rest or uniform rectilinear motion, if forces do not act on it or the action of other forces is compensated.
With a uniform movement of this box on the horizontal floor, the force F with which the box is pulled is compensated by the friction force Ffr.
F = Ftr.
F = 0.05 * P.
F = 0.05 * 500 N = 25 N.
Answer: for uniform rectilinear movement, force F = 25 N.
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