A boy weighing 30 kg while standing on skates horizontally throws a stone weighing 1 kg, the initial velocity of the stone

A boy weighing 30 kg while standing on skates horizontally throws a stone weighing 1 kg, the initial velocity of the stone is 3 m / s. Determine the boy’s speed after throwing.

Given:
m1 = 30kg
m2 = 1kg
V2 = 3m / s
V1-?
Decision:
According to the law of conservation of momentum
m1v01 + m2v02 = m1v1 + m2v2
V2 = m2v2 / m1
V2 = 1 * 3/30 = 0.1 m / s
Answer: the boy’s speed after throwing 0.1m / s



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