A boy weighing 40 kg and his father weighing 100 kg are on skis. The length of the boy’s skis is -1.4 m, and the length of his father’s

A boy weighing 40 kg and his father weighing 100 kg are on skis. The length of the boy’s skis is -1.4 m, and the length of his father’s skis is -2 m. Determine the pressure that the skis of the boy and his father put on the snow if the width of their skis is the same and equal to 10 cm.

Calculate the pressure using the formula:
P = F / S, where F is the pressure force (F = m * g, where m is the mass, g is the acceleration of gravity (g = 10 m / s²)), S is the area of the skis.
Boy’s pressure on snow:
P1 = F1 / S1 = m1 * g / S1, where m1 = 40 kg, S1 = 2 * a * b (a = 1.4 m, b = 10 cm = 0.1 m).
P1 = 40 * 10 / (2 * 1.4 * 0.1) = 1429 Pa.
Father’s pressure on snow:
P2 = F2 / S2 = m2 * g / S2, where m2 = 100 kg, S2 = 2 * a * b (a = 2 m, b = 10 cm = 0.1 m).
P2 = 100 * 10 / (2 * 2 * 0.1) = 2500 Pa.
Answer: The boy’s pressure is 1429 Pa, the father’s pressure is 2500 Pa.



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