A boy weighing 40 kg is standing on the floor. What pressure does he exert on the floor if the total area

A boy weighing 40 kg is standing on the floor. What pressure does he exert on the floor if the total area of the soles of his boots in contact with the floor is 250 cm?

Data: m (weight of a boy standing on the floor) = 40 kg; Stot. (total area of the soles of the boy’s shoes) = 250 cm2 (250 * 10-4 m2, 0.025 m2).

Reference values: g (acceleration due to gravity) = 9.81 m / s2.

The pressure that the boy will produce on the floor is equal to the ratio of the force of gravity acting on him and the total area of the shoes: P = Ft / Stotal. = m * g / Stot.

Calculation: P = 40 * 9.81 / 0.025 = 15 696 Pa.

Answer: The boy produces a pressure of 15 696 Pa on the floor.