A boy weighing 50 kg jumps from a stationary boat weighing 200 kg. Towards the horizon at a speed of 5 meters
| February 22, 2021 | education
A boy weighing 50 kg jumps from a stationary boat weighing 200 kg. Towards the horizon at a speed of 5 meters per second. What is the speed of the boat after the jump?
We calculate the boat speed using the momentum conservation law:
m1V1 = m2V2, where m1 is the mass of the boat (m1 = 200 kg), V1 is the speed of the boat (m / s), m2 is the weight of the boy (m2 = 50 kg), V2 is the speed of the boy (V2 = 5 m / s) …
Let’s express and calculate the speed of the boat:
V1 = m2V2 / m1 = 50 * 5/200 = 250/200 = 1.25 m / s.
Answer: After the boy’s jump, the boat acquired a speed of 1.25 m / s.
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