A brown-eyed man married a blue-eyed woman, they both have brown-eyed children

A brown-eyed man married a blue-eyed woman, they both have brown-eyed children, determine the genotype of all family members.

A – brown eyes, a – blue eyes. The brown-eyed man has the XYAA genotype and is married to the blue-eyed woman, the XXaa genotype. Thus, we have:

XYAA × XXaa

Gametes: XA YA Xa

Genotypes of the alleged children: XXAA daughter with brown eyes, XYAa son also with brown eyes.



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