A brown-eyed woman (heterozygous) married a blue-eyed man, determine the genotype
| September 8, 2021 | education
A brown-eyed woman (heterozygous) married a blue-eyed man, determine the genotype of the children and the phenotype of the children.
1) A – brown eyes, and – blue.
The genotype of the mother is Aa, the father is aa.
2) To find the genotypes of children, it is necessary to draw up a crossing scheme.
Parent genotypes: Aa x aa,
Parent gametes: A, a x a,
Possible offspring genotypes: Aa, aa.
3) Half of the children (50%) will have brown eyes, half will have blue eyes.
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