A brown-eyed woman whose father is blue-eyed, color-blind, her husband is blue-eyed with normal vision.

A brown-eyed woman whose father is blue-eyed, color-blind, her husband is blue-eyed with normal vision. the likelihood of children with color blindness with brown eyes?

Brown eye color (A) dominates blue (a), and color blindness is a recessive trait that is linked to the X chromosome (Xd), normal color vision is dominant (XD).
1) First, find the mother’s genotype.
She inherited the alleles a and Xd from her father, that is, her genotype is AaXDXd.
2) write down the solution scheme:
Parents: (mother) AaXDXd x aaXDY (father).
Gametes: AXD, AXd, aXD, aXd x aXD, aY.
Offspring: AaXDXD (brown-eyed healthy girl), AaXDY (brown-eyed healthy boy), AaXDXd (brown-eyed carrier girl), AaXdY (brown-eyed color-blind boy), aaXDXD (blue-eyed girl), aaXDY (blue-eyed girl, aaX healthy D) carrier), aaXdY (blue-eyed color-blind boy).
There are 8 genotypes in total, of which only one (AaXdY) corresponds to a color-blind boy with brown eyes.