A bucket of 8 kg masks was lifted from a well 5 m deep. the work is done at the same time?

Task data: h (depth of the well, change in the height of the bucket relative to the bottom of the well) = 5 m; m (bucket weight) = 8 kg.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The work that is done during lifting will be equal to the change in the potential energy of the bucket: A = ΔEp = m * g * h.

Calculation: A = 8 * 10 * 5 = 400 J.

Answer: The work perfect when lifting is 400 J.