A bucket of hot water, the temperature of which is 100 degrees, and the mass of 10 kg cools down

A bucket of hot water, the temperature of which is 100 degrees, and the mass of 10 kg cools down to room temperature (20 degrees) how much heat does the water give to the surrounding bodies and air

To find the value of the thermal energy given by the indicated bucket of hot water, we use the formula: Q = Sv * m * (tк – t).

Constants and variables: Sv – beats. heat capacity of water (Sv = 4.2 * 10 ^ 3 J / (kg * K)); m is the mass of water in the specified bucket (m = 10 kg); tк – room temperature (tк = 20 ºС); t – initial water temperature (t = 100 ºС).

Calculation: Q = Sv * m * (tk – t) = 4.2 * 10 ^ 3 * 10 * (100 – 20) = 3.36 * 10 ^ 6 J.

Answer: Air and surrounding bodies will receive 3.36 MJ of thermal energy from 10 kg of water.