A bucket weighing 0.5 tons is lowered into the mine. For the first 0.5 minutes, it covers 360m.
| December 14, 2020 | education
A bucket weighing 0.5 tons is lowered into the mine. For the first 0.5 minutes, it covers 360m. Find the tensile force of the rope to which the bucket is suspended.
P = T (Bucket weight is equal to rope pulling force)
T = m * (g-a) (Weight decreases as the bucket goes down)
a = \ frac {2h} {t ^ 2} = \ frac {720} {900} = 0.8m / c ^ 2
T = m * (g-a) = 500 * (9.8-0.8) = 4500H = 4.5kH
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