A bullet fired from a rifle with an initial speed of 1000 m / s at an altitude of 10 m fell to the ground at a speed of 500 m / s.

| January 12, 2021 | education

A bullet fired from a rifle with an initial speed of 1000 m / s at an altitude of 10 m fell to the ground at a speed of 500 m / s. What work was spent during the flight to overcome the force of air resistance, if the weight of the bullet is 1 N.

Data: V0 (muzzle velocity of a given rifle bullet) = 1000 m / s; h0 (initial height) = 10 m; V (bullet velocity at the moment of fall) = 500 m / s; P (bullet weight) = 1 N.
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
The work expended by the bullet to overcome the force of air resistance is determined by the formula: A = Efull1 – Efull2 = (m * V0 ^ 2/2 + m * g * h0) – m * V ^ 2/2 = P * V0 ^ 2 / 2g + P * h0 – P * V ^ 2 / 2g.
Let’s perform the calculation: A = 1 * 1000 ^ 2 / (2 * 10) + 1 * 10 – 1 * 500 ^ 2 / (2 * 10) = 37510 J.



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