A bullet flying at a speed of 200 km / h2 hits an obstacle and penetrates it to a depth of 25 cm

A bullet flying at a speed of 200 km / h2 hits an obstacle and penetrates it to a depth of 25 cm. Determine the acceleration of the bullet inside the obstacle.

These tasks: V0 (flight speed of a given bullet before hitting an obstacle) = 200 km / h (in SI V0 = 55.56 m / s); H (depth of penetration of a bullet into an obstacle, distance traveled) = 25 cm (in SI H = 0.25 m); V (final speed) = 0 m / s.

We express the acceleration of a given bullet inside the obstacle from the formula: S = H = (V ^ 2 – V0 ^ 2) / 2a, whence a = (V ^ 2 – V0 ^ 2) / 2H = (0 ^ 2 – V0 ^ 2) / 2H = -V0 ^ 2 / 2H.

Let’s perform the calculation: a = -55.56 ^ 2 / (2 * 0.25) = -6173 m / s2.

Answer: Acceleration of the bullet inside the obstacle was -6173 m / s2.