A bullet flying at a speed of 400 m / s hits an obstacle and penetrates it to a depth of 32 cm.

| July 25, 2021 | education

A bullet flying at a speed of 400 m / s hits an obstacle and penetrates it to a depth of 32 cm. Find the acceleration and travel time of the bullet inside the obstacle. At what depth will the bullet speed decrease by 4 times? The bullet movement is considered to be equally slow.

Given: equal slow motion; V0 (initial speed) = 400 m / s; h (depth of penetration of a bullet into an obstacle) = 32 cm = 0.32 m; V (considered speed) = 0.25V0.

1) Constant acceleration: a = V0 ^ 2 / 2h = 400 ^ 2 / (2 * 0.3 ^ 2) = 250,000 m / s2 = 250 km / s2.

2) The duration of the bullet movement in the obstacle: t = V0 / a = 400/250000 = 0.0016 s = 1.6 ms.

3) The depth at which the bullet speed decreased by 4 times: h = (V0 ^ 2 – V ^ 2) / 2a = (V0 ^ 2 – 0.0625V0 ^ 2) / 2a = (400 ^ 2 – 0.0625 * 400 ^ 2) / (2 * 250000) = 0.3 m.



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