A bullet flying at a speed of 400m / s hits the earthen shaft and penetrates to a depth of 36cm.

A bullet flying at a speed of 400m / s hits the earthen shaft and penetrates to a depth of 36cm. Find t movement of the bullet inside the shaft, acceleration and velocity at a depth of 18 cm.

Given: V0 (initial speed of movement) = 400 m / s; h (depth of penetration of a bullet into the earthen wall) = 36 cm = 0.36 m; h1 (considered depth) = 18 cm = 0.18 m.

1) Constant acceleration: a = (V0 ^ 2 – V ^ 2) / 2h = (400 ^ 2 – 0 ^ 2) / (2 * 0.36) = 222222.2 m / s2.

2) The time of movement of the bullet in the earthen wall: t = V0 / a = 400 / 222222.2 = 0.0018 s = 1.8 ms.

3) The speed of a given bullet at a depth of 18 cm: h1 = (V0 ^ 2 – V ^ 2) / 2a and V = √ (V0 ^ 2 – 2a * h1) = √ (400 ^ 2 – 2 * 222222.2 * 0 , 18) = 282.84 m / s.