A bullet flying at a speed of 500m / s hits the ground and gets stuck at a depth of 1m.

A bullet flying at a speed of 500m / s hits the ground and gets stuck at a depth of 1m. Determine the acceleration of the bullet.

V0 = 500 m / s.

S = 1 m.

V = 0 m / s.

a -?

Since the bullet has stopped in the ground, then its final velocity is V = 0 m / s.

If we consider the movement of a bullet in the ground to be uniformly accelerated, then its acceleration a can be expressed by the formula: a = (V0 ^ 2 – V ^ 2) / 2 * S = V0 ^ 2/2 * S, where V0, V are the initial and final speed of movement bullets, S – bullet path.

We substitute the data from the condition of the problem into the formula for acceleration: a = (500 m / s) ^ 2/2 * 1 m = 125000 m / s2.

Answer: the acceleration of the bullet when it moved into the ground was a = 125000 m / s2.