A bullet weighing 10 g flies at a speed of 400 m / s, hits the board and gets stuck in it at a depth of 20 cm.
| February 15, 2021 | education
A bullet weighing 10 g flies at a speed of 400 m / s, hits the board and gets stuck in it at a depth of 20 cm. What is the modulus of the board’s average resistance force.
Data: m (bullet weight) = 10 g (0.01 kg); V (bullet velocity before hitting the board) = 400 m / s; h (depth traveled by the bullet in the board, distance traveled) = 20 cm (0.2 m).
To determine the modulus of the average resistance force of the board, we use the equality: m * V ^ 2/2 = A = Fcopr * h, whence Fcopr = m * V ^ 2 / (2 * h).
Calculation: Fcopr = 0.01 * 400 ^ 2 / (2 * 0.2) = 4000 N or 4 kN.
Answer: The module of the average resistance force of the board is 4 kN.
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