A bullet weighing 10 g flies horizontally at a speed of 700 m / s. It falls into a 990 g box on a horizontal

| April 4, 2021 | education

A bullet weighing 10 g flies horizontally at a speed of 700 m / s. It falls into a 990 g box on a horizontal surface and gets stuck in it. How far will the box go to stop if the coefficient of friction between the box and the surface is 0.05?

Data: mp (bullet weight) = 10 g = 0.01 kg; Vp (bullet speed before hitting the box) = 700 m / s; mя (box weight) = 990 g = 0.99 kg; μ (coefficient of friction) = 0.05; g (acceleration due to gravity) ≈ 10 m / s2.

1) The speed of the box after being hit by a bullet: V = mp * Vp / (mp + my) = 0.01 * 700 / (0.01 + 0.99) = 7 m / s.

2) The path traversed by the box: (mp + my) * V ^ 2/2 = Ftr. * S = μ * (mа + mп) * g * S, whence S = (mа + mа) * V ^ 2 / (2 * μ * (my + mp) * g) = V ^ 2 / (2 * μ * g) = 7 ^ 2 / (2 * 0.05 * 10) = 49 m.



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