A bullet weighing 10 g, flying at a speed of 100 m / s, hits a resting wooden block weighing 490 g and gets stuck in it.

A bullet weighing 10 g, flying at a speed of 100 m / s, hits a resting wooden block weighing 490 g and gets stuck in it. How fast will the block move immediately after being hit by a bullet?

Given: mp (bullet mass) = 10 g = 0.01 kg; Vp (bullet speed before hitting the bar) = 100 m / s; mb (bar weight) = 490 g = 0.49 kg.

To calculate the speed of a wooden block after a bullet hit, we apply the law of conservation of momentum: mp * Vp = (mp + mb) * V and V = mp * Vp / (mp + mb).

Calculation: V = 0.01 * 100 / (0.01 + 0.49) = 2 m / s.

Answer: Immediately after being hit by a bullet, the wooden block will begin to move at a speed of 2 m / s.



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