A bullet weighing 10 g, flying at a speed of 600 m / s, hits a body with a mass of 590 g lying motionless

| June 20, 2021 | education

A bullet weighing 10 g, flying at a speed of 600 m / s, hits a body with a mass of 590 g lying motionless on a horizontal surface and gets stuck in it. As a result of the collision, the body was displaced by 20 m. Calculate the coefficient of friction between the body and the surface.

Data: m (bullet mass) = 10 g = 0.01 kg; Vp (bullet speed before hitting a stationary body) = 600 m / s; mt (body weight) = 590 g = 0.59 kg; S (body displacement) = 20 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) The speed with which the stationary body began to move: mp * Vp = (mp + mt) * V and V = mp * Vp / (mp + mt) = 0.01 * 600 / (0.01 + 0.59) = 10 m / s.

2) Coefficient of friction: (mp + mt) * V ^ 2/2 = A = Ftr * S = μ * (mp + mt) * g * S and μ = V ^ 2 / (2 * g * S) = 10 ^ 2 / (2 * 10 * 20) = 0.25.



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