A bullet weighing 10 g, flying horizontally at a constant speed of 400 ms, hits the obstacle and stops.
| December 11, 2020 | education
A bullet weighing 10 g, flying horizontally at a constant speed of 400 ms, hits the obstacle and stops. What is the change in the momentum of the bullet?
Impulse change: <> p = mv – mv0, where <> designation “delta” – change, v – speed.
Given: m = 0.01kg v0 = 400m / s v = 0m / s Find: <> p
Decision:
<> p = mv-mv0 = m (v-v0) <> p = 0.01 * (0-400) = – 4 kg * m / s
Answer: <> p = 4 kg * m / s
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