A bullet weighing 10 grams flies horizontally at a speed of 200 m / s, hits an obstacle and stops.

| December 16, 2020 | education

A bullet weighing 10 grams flies horizontally at a speed of 200 m / s, hits an obstacle and stops. What is the momentum of a bullet before hitting an obstacle? What momentum did the bullet get from the obstacle?

To find the impulse of the impact, we need to use this formula
p = m * V
It seems, take and substitute, but no. Before substituting the values ​​of speed and mass, we need to convert the mass from grams to kilograms, 10 grams is 0.01 kilograms, Now you can substitute values ​​and find momentum
p = 0.01 * 200 = 2 (kg * m / s)
And the answer to the second question
2 (kg * m / s). momentum says
The impulse does not go anywhere, it can only be transformed. Roughly speaking, the impulse at the beginning is equal to the impulse at the end. The bullet gave all its impulse to the obstacle and if it moved, it would be possible to find its impulse, and it would be equal to the impulse of the bullet. But that would be only in no air space, because the bullet spends momentum to overcome the friction force.



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