A bullet weighing 10g, flying horizontally at a speed of 400m / s, hits the obstacle and stops.

A bullet weighing 10g, flying horizontally at a speed of 400m / s, hits the obstacle and stops. What is the change in the momentum of the bullet?

To find the change in impulse, we subtract the final impulse from the initial impulse or, on the contrary, add, in our case, subtract
p1-p2 = p
We know p2, because the tasks say that “… hits an obstacle and stops”
So V = 0. and this means p2 = 0
Now, to find p1, we need to convert 10 grams to kilograms
10 grams = 0.01 kilograms
But now you can substitute the values of e
p = 0.01 * 400 = 4 (kg * m / s)
Answer: p = 4 (kg * m / s)