A bullet with a mass of 5 g, flying in a horizontal direction at a speed of 200 m / s

A bullet with a mass of 5 g, flying in a horizontal direction at a speed of 200 m / s, hits a ball with a mass of 195 g lying on a table and gets stuck in it, does the ball gain speed?

mp = 5 g = 0.005 kg.
Vp = 200 m / s.
mw = 195 g = 0.195 kg.
V -?
According to the law of conservation of momentum: the momentum of a closed system does not change.
Before hitting the ball, the impulse was: mp * Vp, mp is the mass of the bullet, Vp is the speed of the bullet.
After the bullet hits the ball, the impulse of the system will be: (mn + mw) * V, where mw is the mass of the ball, V is the speed of the ball with the bullet.
mp * Vp = (mp + msh) * V.
V = mp * Vp / (mp + msh).
V = 0.005 kg * 200 m / s / (0.005 kg + 0.195 kg) = 5 m / s.
Answer: the ball acquires a speed V = 5 m / s.



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