A bullet with a mass of m = 10g, flying at a speed of v = 600m / s, hit a ballistic pendulum with a mass of m = 5kg

| September 5, 2021 | education

A bullet with a mass of m = 10g, flying at a speed of v = 600m / s, hit a ballistic pendulum with a mass of m = 5kg and got stuck in it. To what height did the pendulum rise after being pumped out after the impact?

m = 10 g = 0.01 kg.

Vp = 600 m / s.

g = 9.8 m / s2.

m = 5 kg.

h -?

The height of the ballistic pendulum lifting h will be found from the law of conservation of total mechanical energy: (m + m) * v = (m + m) * g * h, where v is the speed of the pendulum with a bullet stuck in it, immediately after the hit.

h = (m + m) * v / (m + m) * g = v / g.

The speed of the pendulum with a bullet stuck in it, immediately after the hit, is found from the law of conservation of momentum: m * Vp = (m + m) * v.

v = m * Vp / (m + m).

v = 0.01 kg * 600 m / s / (0.01 kg + 5 kg) = 1.2 m / s.

h = 1.2 m / s / 9.8 m / s2 = 0.12 m.

Answer: the ballistic pendulum will rise to a height of h = 0.12 m.



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