A buoyant force equal to 18.8 kN acts on a body floating in kerosene. Find the volume of this body

A buoyant force equal to 18.8 kN acts on a body floating in kerosene. Find the volume of this body if the density of kerosene is 800 kg / m3.

Problem data: Fa (buoyancy force) = 18.8 kN (18.8 * 10 ^ 3 N); we believe that the body is completely immersed in kerosene.

Reference values: g (acceleration due to gravity) ≈ 10 N / kg; according to the condition ρк (kerosene density) = 800 kg / m3.

The volume of the body under consideration can be expressed from the formula: Fa = ρк * g * V, whence V = Fa / (ρк * g).

Let’s calculate: V = 18.8 * 10 ^ 3 / (800 * 10) = 2.35 m3.

Answer: The body has a volume of 2.35 m3.