A bus and then a car departed from the bus station with an interval of 0.5 minutes in one direction, the speeds of which

A bus and then a car departed from the bus station with an interval of 0.5 minutes in one direction, the speeds of which are respectively equal to 10 m / s and 20 m / s. How far from the bus station will the car catch up with the bus?

Calculate the distance traveled by any body using the formula:
S = V * t, where V is the speed of the body (m / s), t is the time of movement (s).
Distance covered by the bus:
S1 = V1 * t1, where V1 = 10 m / s, t1 = 30 + t2.
Distance traveled by car:
S2 = V2 * t2, where V2 = 20 m / s.
When the car catches up with the bus it will be correct: S1 = S2.
V1 * t1 = V2 * t2.
V1 * (30 + t2) = V2 * t2.
10 * (30 + t2) = 20 * t2.
300 + 10 * t2 = 20 * t2.
t2 = 30 s.
S2 = V2 * t2 = 20 * 30 = 600 m.
Answer: The car will catch up with the bus after 600 m.