A bus weighing 15 tons moves under the action of a force of 15 Kn. The friction coefficient is 0.1. How fast is the bus moving?

We calculate the acceleration of the bus using Newton’s second law:

ma = F – Ftr, where m (bus mass) = 15 t or 15000 kg, F (force imparting acceleration) = 15 kN = 15000 N, Ftr (sliding friction force) = μ * m * g (μ – coefficient of friction (μ = 0.1), g is the acceleration of gravity (g = 10 m / s2)).

ma = F – μ * m * g.

a = (F – μ * m * g) / m.

Payment:

a = (15000 – 0.1 * 15000 * 10) / 15000 = 0 m / s2.

Answer: The acceleration of the bus is 0 m / s2, the action of the given force cannot overcome the friction force.