A bus weighing 15 tons starts to move under the influence of a force of 15 kN.

A bus weighing 15 tons starts to move under the influence of a force of 15 kN. What is the acceleration of the bus if the resistance force acting on it is 4.5 kN.

So, 2 forces act on the bus: this is the force driving the car (directed in the direction of movement) and the force of friction (resistance), which is directed in the direction opposite to the movement. According to Newton’s second law, the formula in this case will look like:

ma = F – Ftr,

where, m is the mass of the bus, = 15t = 15,000 kg;

F – traction force, = 15 kN = 15,000 N;

Ftr – resistance force, = 4.5 kN = 4500 N.

a – acceleration, m / s ^ 2.

From the formula we find the acceleration: a = (F – Ftr) / m = (15,000 – 4500) / 15,000 = 0.7.

Answer: the acceleration of the bus is 0.7 m / s ^ 2.