A capacitor with a capacity of 800 microfarads is charged to a potential difference of 300 V.

A capacitor with a capacity of 800 microfarads is charged to a potential difference of 300 V. Determine the energy of the electric field of the capacitor.

The energy of the electric field of a charged capacitor can be calculated using the formula:
Wp = (C * U ^ 2) / 2, where C is the capacitance of the capacitor (C = 800 μF = 800 * 10 ^ -6 F), U is the potential difference (U = 300 V).
Let’s calculate the energy of the electric field of a charged capacitor:
Wp = (C * U ^ 2) / 2 = ((800 * 10 ^ -6) * 300 ^ 2) / 2 = 36 J.
Answer: The energy of the electric field of a charged capacitor is 36 J.