# A car moving at a speed of 10 m / s when braking stopped after 5 seconds.

A car moving at a speed of 10 m / s when braking stopped after 5 seconds. What path did he go when braking if he was moving at uniform acceleration?

Initial conditions: V0 (vehicle speed before braking) = 10 m / s; V (final speed, the car will stop) = 0 m / s; t (deceleration duration) = 5 s; a = const.

1) Determine the acceleration of the car:

V = V0 + a * t; a = -V0 / t = -10 / 5 = – 2 m / s (slow motion).

2) Calculate the distance that the car traveled when braking:

S = (V ^ 2 – V0 ^ 2) / 2a = (0 – 10 ^ 2) / (2 * (-2)) = -100 / (-4) = 100/4 = 25 m.

Answer: When braking, the car will travel 25 meters.

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