A car moving at a speed of 36 km / h on a road section with a slope began to move with an acceleration of 0.1 m / s squared.

| January 16, 2021 | education

A car moving at a speed of 36 km / h on a road section with a slope began to move with an acceleration of 0.1 m / s squared. At the end of the slope, its speed reached 54 km / h. How long was the slope?

V0 = 36 km / h = 10 m / s.

V = 54 km / h = 15 m / s.

a = 0.1 m / s2.

S -?

Since the car moves down the slope with uniform acceleration, its path is expressed by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the speed at the beginning of the slope, t is the time of movement along the slope, a is the acceleration during movement.

The time of movement of the car along the slope t is expressed by the formula: t = (V – V0) / a.

t = (15 m / s – 10 m / s) / 0.1 m / s2 = 50 s.

S = 10 m / s * 50 s + 0.1 m / s2 * (50 s) ^ 2/2 = 625 m.

Answer: the length of the slope along which the car was moving was S = 625 m.



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