A car of mass m moving at a speed v collides with a stationary car of mass 2m.

| August 1, 2021 | education

A car of mass m moving at a speed v collides with a stationary car of mass 2m. what is the total impulse of two cars at the moment of collision.

Given:

m is the mass of a moving car, kilogram;

v is the speed at which the carriage is moving, meter / second;

2 * m is the mass of a stationary car.

It is required to determine p (kilogram * meter / second) – the total impulse of two cars at the moment of collision.

By the condition of the problem, the second car is motionless. Then, according to the law of conservation of energy:

v1 * (m + 2 * m) = m * v + 2 * m * 0, where m + 2 * m is the total mass of two cars, 0 is the speed of a stationary car;

v1 * 3 * m = m * v;

v1 = m * v / (3 * m) = v / 3.

Then the total impulse will be equal to:

p = v1 * 3 * m = m * v * 3/3 = m * v.

Answer: the total impulse of two cars at the moment of collision will be equal to m * v.



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